To Check Perfect Number | Function | For Loop | Python

Python Program To check whether Entered Number is Perfect Number or Not through user defined Function with For Loop.

According to Wikipedia : In number theory, a perfect number is a positive integer that is equal to the sum of its proper positive divisors, that is, the sum of its positive divisors excluding the number itself (also known as its aliquot sum). Equivalently, a perfect number is a number that is half the sum of all of its positive divisors (including itself).

Example : The first perfect number is 6, because 1, 2, and 3 are its proper positive divisors, and 1 + 2 + 3 = 6. Equivalently, the number 6 is equal to half the sum of all its positive divisors: ( 1 + 2 + 3 + 6 ) / 2 = 6. The next perfect number is 28 = 1 + 2 + 4 + 7 + 14. This is followed by the perfect numbers 496 and 8128.

Coding of Above Program:

1. def divisor(n):
2.     l=[n]
3.     for i in range(1,n):
4.         if(n%i==0):
5.             l.append(i)
6.     return l
7. print('''To Check whether the Entered Number
8. is Perfect Number or Not.''')
9. n=int(input("Enter Number="))
10. div=divisor(n)
11. sum=0
12. for i in range(0,len(div)):
13.     sum+=div[i]
14. if(sum/2==n):
15.     print("Entered Number is Perfect Number")
16. else:
17.     print("Entered Number is Not Perfect Number")

• Screenshot of Above Coding in Visual Studio Code with Output.

Perfect Number in Python

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